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PS2/doc.tex
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PS2/doc.tex
@ -680,9 +680,28 @@ axis([0 1e-9 0 0.04]);
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\item %4a
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\item %4a
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\begin{figure}[H]
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\centering
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\begin{subfigure}{0.5\textwidth}
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\centering
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\includegraphics[width=\textwidth]{q4a_e1.png}
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\caption{}
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\end{subfigure}%
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\begin{subfigure}{0.5\textwidth}
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\centering
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\includegraphics[width=\textwidth]{q.png}
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\caption{}
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\end{subfigure}
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\caption{(a),(b) Previous plots but with the classical momentum marked in red.}
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\end{figure}
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% TODO I really don't like this explanation...
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% TODO I really don't like this explanation...
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An \( a \) value of \( 0.62 \angstrom \) was chosen, in order to provide an adequately
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An \( a \) value of \( 0.53 \angstrom \) was chosen in order to provide an adequately
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shaped graph without sacrificing too much computation time.
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shaped graph without sacrificing too much computation time and ensure that the first two
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numerical energies correspond to the given experimental results. The experimental results are
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\(\SI{0.14395}{\electronvolt}\) and \(\SI{0.43185}{\electronvolt} \) for the first and second energy levels
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respectively, and the numerical results with our chosen \(a\) are \(\SI{0.0.14386}{\electronvolt}\) and \(\SI{0.43140}{\electronvolt} \)
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% maybe talk about normalization?
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% maybe talk about normalization?
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@ -692,7 +711,13 @@ axis([0 1e-9 0 0.04]);
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\lipsum[1]
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\lipsum[1]
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\item %4bii
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\item %4bii
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Between \( 0V \) and \( 0.25V \), only the first energy level is carrying any current.
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This current drops to 0 above \( 0.25V\) because the coupling between the contacts and that
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energy level drops to 0, meaning no electrons can transfer.
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Between \(0.4V\) and \(0.65V\), only the second energy level is carrying current.
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This energy level stops dropping current because it's shifted energy drops below
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the threshold where the contacts have any coupling with it.
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\item %4biii
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\item %4biii
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@ -18,7 +18,7 @@ w0 = (0.2879*q/hbar);
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% YOU MUST ENTER AN APPROPRIATE VALUE OF "a"
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% YOU MUST ENTER AN APPROPRIATE VALUE OF "a"
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a = 12 / sqrt(m*w0/hbar) / 100;
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a = 12 / sqrt(m*w0/hbar) / 120;
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beta = sqrt(m*w0/hbar);
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beta = sqrt(m*w0/hbar);
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x = [-6/beta:a:6/beta];
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x = [-6/beta:a:6/beta];
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N = length(x);
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N = length(x);
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